ln(e^2x-1)=5

Solution for ln(e^2x-1)=5 equation:

Simplifying
ln(e2x + -1) = 5

Reorder the terms:
ln(-1 + e2x) = 5
(-1 * ln + e2x * ln) = 5

Reorder the terms:
(e2lnx + -1ln) = 5
(e2lnx + -1ln) = 5

Solving
e2lnx + -1ln = 5

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add 'ln' to each side of the equation.
e2lnx + -1ln + ln = 5 + ln

Combine like terms: -1ln + ln = 0
e2lnx + 0 = 5 + ln
e2lnx = 5 + ln

Divide each side by 'lnx'.
e2 = 5l-1n-1x-1 + x-1

Simplifying
e2 = 5l-1n-1x-1 + x-1

Reorder the terms:
e2 + -5l-1n-1x-1 + -1x-1 = 5l-1n-1x-1 + -5l-1n-1x-1 + x-1 + -1x-1

Combine like terms: 5l-1n-1x-1 + -5l-1n-1x-1 = 0
e2 + -5l-1n-1x-1 + -1x-1 = 0 + x-1 + -1x-1
e2 + -5l-1n-1x-1 + -1x-1 = x-1 + -1x-1

Combine like terms: x-1 + -1x-1 = 0
e2 + -5l-1n-1x-1 + -1x-1 = 0

The solution to this equation could not be determined.